3y+3(1-y)=7y-18

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Solution for 3y+3(1-y)=7y-18 equation: 



3y+3(1-y)=7y-18

We move all terms to the left:

3y+3(1-y)-(7y-18)=0

We add all the numbers together, and all the variables

3y+3(-1y+1)-(7y-18)=0

We multiply parentheses

3y-3y-(7y-18)+3=0

We get rid of parentheses

3y-3y-7y+18+3=0

We add all the numbers together, and all the variables

-7y+21=0

We move all terms containing y to the left, all other terms to the right

-7y=-21

y=-21/-7

y=+3

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