3y+3(y-2)=7y-3(y-10)

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Solution for 3y+3(y-2)=7y-3(y-10) equation: 



3y+3(y-2)=7y-3(y-10)

We move all terms to the left:

3y+3(y-2)-(7y-3(y-10))=0

We multiply parentheses

3y+3y-(7y-3(y-10))-6=0



We calculate terms in parentheses: -(7y-3(y-10)), so:

7y-3(y-10)

We multiply parentheses

7y-3y+30

We add all the numbers together, and all the variables

4y+30

Back to the equation:

-(4y+30)



We add all the numbers together, and all the variables

6y-(4y+30)-6=0

We get rid of parentheses

6y-4y-30-6=0

We add all the numbers together, and all the variables

2y-36=0

We move all terms containing y to the left, all other terms to the right

2y=36

y=36/2

y=18

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