3y+3(y-6)=3(y+1)-2

Solution for 3y+3(y-6)=3(y+1)-2 equation:

3y+3(y-6)=3(y+1)-2

We move all terms to the left:

3y+3(y-6)-(3(y+1)-2)=0

We multiply parentheses

3y+3y-(3(y+1)-2)-18=0


We calculate terms in parentheses: -(3(y+1)-2), so:

3(y+1)-2

We multiply parentheses

3y+3-2

We add all the numbers together, and all the variables

3y+1

Back to the equation:

-(3y+1)


We add all the numbers together, and all the variables

6y-(3y+1)-18=0

We get rid of parentheses

6y-3y-1-18=0

We add all the numbers together, and all the variables

3y-19=0

We move all terms containing y to the left, all other terms to the right

3y=19

y=19/3

y=6+1/3