3y+3+2y+5=48

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Solution for 3y+3+2y+5=48 equation:



3y+3+2y+5=48
We move all terms to the left:
3y+3+2y+5-(48)=0
We add all the numbers together, and all the variables
5y-40=0
We move all terms containing y to the left, all other terms to the right
5y=40
y=40/5
y=8

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