3y+3+2y+5=48

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Solution for 3y+3+2y+5=48 equation: 



3y+3+2y+5=48

We move all terms to the left:

3y+3+2y+5-(48)=0

We add all the numbers together, and all the variables

5y-40=0

We move all terms containing y to the left, all other terms to the right

5y=40

y=40/5

y=8

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