3y+3-3(-5y-3)=4(y-1)

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Solution for 3y+3-3(-5y-3)=4(y-1) equation: 



3y+3-3(-5y-3)=4(y-1)

We move all terms to the left:

3y+3-3(-5y-3)-(4(y-1))=0

We multiply parentheses

3y+15y-(4(y-1))+9+3=0



We calculate terms in parentheses: -(4(y-1)), so:

4(y-1)

We multiply parentheses

4y-4

Back to the equation:

-(4y-4)



We add all the numbers together, and all the variables

18y-(4y-4)+12=0

We get rid of parentheses

18y-4y+4+12=0

We add all the numbers together, and all the variables

14y+16=0

We move all terms containing y to the left, all other terms to the right

14y=-16

y=-16/14

y=-1+1/7

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