3y+3-3(-5y-3)=4y-4

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Solution for 3y+3-3(-5y-3)=4y-4 equation: 



3y+3-3(-5y-3)=4y-4

We move all terms to the left:

3y+3-3(-5y-3)-(4y-4)=0

We multiply parentheses

3y+15y-(4y-4)+9+3=0

We get rid of parentheses

3y+15y-4y+4+9+3=0

We add all the numbers together, and all the variables

14y+16=0

We move all terms containing y to the left, all other terms to the right

14y=-16

y=-16/14

y=-1+1/7

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