3y+3-3(-5y-3)=6(y-1)

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Solution for 3y+3-3(-5y-3)=6(y-1) equation: 



3y+3-3(-5y-3)=6(y-1)

We move all terms to the left:

3y+3-3(-5y-3)-(6(y-1))=0

We multiply parentheses

3y+15y-(6(y-1))+9+3=0



We calculate terms in parentheses: -(6(y-1)), so:

6(y-1)

We multiply parentheses

6y-6

Back to the equation:

-(6y-6)



We add all the numbers together, and all the variables

18y-(6y-6)+12=0

We get rid of parentheses

18y-6y+6+12=0

We add all the numbers together, and all the variables

12y+18=0

We move all terms containing y to the left, all other terms to the right

12y=-18

y=-18/12

y=-1+1/2

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