3y+3-y=1+y-2

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Solution for 3y+3-y=1+y-2 equation: 



3y+3-y=1+y-2

We move all terms to the left:

3y+3-y-(1+y-2)=0

We add all the numbers together, and all the variables

3y-y-(y-1)+3=0

We add all the numbers together, and all the variables

2y-(y-1)+3=0

We get rid of parentheses

2y-y+1+3=0

We add all the numbers together, and all the variables

y+4=0

We move all terms containing y to the left, all other terms to the right

y=-4

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