3y+33=9(y+1)

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Solution for 3y+33=9(y+1) equation: 



3y+33=9(y+1)

We move all terms to the left:

3y+33-(9(y+1))=0



We calculate terms in parentheses: -(9(y+1)), so:

9(y+1)

We multiply parentheses

9y+9

Back to the equation:

-(9y+9)



We get rid of parentheses

3y-9y-9+33=0

We add all the numbers together, and all the variables

-6y+24=0

We move all terms containing y to the left, all other terms to the right

-6y=-24

y=-24/-6

y=+4

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