3y+35=10+7y

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Solution for 3y+35=10+7y equation: 



3y+35=10+7y

We move all terms to the left:

3y+35-(10+7y)=0

We add all the numbers together, and all the variables

3y-(7y+10)+35=0

We get rid of parentheses

3y-7y-10+35=0

We add all the numbers together, and all the variables

-4y+25=0

We move all terms containing y to the left, all other terms to the right

-4y=-25

y=-25/-4

y=6+1/4

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