3y+38=y+12

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Solution for 3y+38=y+12 equation: 



3y+38=y+12

We move all terms to the left:

3y+38-(y+12)=0

We get rid of parentheses

3y-y-12+38=0

We add all the numbers together, and all the variables

2y+26=0

We move all terms containing y to the left, all other terms to the right

2y=-26

y=-26/2

y=-13

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