3y+3=(1-y)-y=-6

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Solution for 3y+3=(1-y)-y=-6 equation: 



3y+3=(1-y)-y=-6

We move all terms to the left:

3y+3-((1-y)-y)=0

We add all the numbers together, and all the variables

3y-((-1y+1)-y)+3=0



We calculate terms in parentheses: -((-1y+1)-y), so:

(-1y+1)-y

We add all the numbers together, and all the variables

-1y+(-1y+1)

We get rid of parentheses

-1y-1y+1

We add all the numbers together, and all the variables

-2y+1

Back to the equation:

-(-2y+1)



We get rid of parentheses

3y+2y-1+3=0

We add all the numbers together, and all the variables

5y+2=0

We move all terms containing y to the left, all other terms to the right

5y=-2

y=-2/5

y=-2/5

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