3y+3=3(y+1)

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Solution for 3y+3=3(y+1) equation: 



3y+3=3(y+1)

We move all terms to the left:

3y+3-(3(y+1))=0



We calculate terms in parentheses: -(3(y+1)), so:

3(y+1)

We multiply parentheses

3y+3

Back to the equation:

-(3y+3)



We get rid of parentheses

3y-3y-3+3=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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