3y+4(2y+3)=133

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Solution for 3y+4(2y+3)=133 equation: 



3y+4(2y+3)=133

We move all terms to the left:

3y+4(2y+3)-(133)=0

We multiply parentheses

3y+8y+12-133=0

We add all the numbers together, and all the variables

11y-121=0

We move all terms containing y to the left, all other terms to the right

11y=121

y=121/11

y=11

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