3y+4(2y-1)=18

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Solution for 3y+4(2y-1)=18 equation:



3y+4(2y-1)=18
We move all terms to the left:
3y+4(2y-1)-(18)=0
We multiply parentheses
3y+8y-4-18=0
We add all the numbers together, and all the variables
11y-22=0
We move all terms containing y to the left, all other terms to the right
11y=22
y=22/11
y=2

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