3y+4(y+6)=13y-18

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Solution for 3y+4(y+6)=13y-18 equation: 



3y+4(y+6)=13y-18

We move all terms to the left:

3y+4(y+6)-(13y-18)=0

We multiply parentheses

3y+4y-(13y-18)+24=0

We get rid of parentheses

3y+4y-13y+18+24=0

We add all the numbers together, and all the variables

-6y+42=0

We move all terms containing y to the left, all other terms to the right

-6y=-42

y=-42/-6

y=+7

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