3y+4(y-3)=5y-3(y-2)

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Solution for 3y+4(y-3)=5y-3(y-2) equation: 



3y+4(y-3)=5y-3(y-2)

We move all terms to the left:

3y+4(y-3)-(5y-3(y-2))=0

We multiply parentheses

3y+4y-(5y-3(y-2))-12=0



We calculate terms in parentheses: -(5y-3(y-2)), so:

5y-3(y-2)

We multiply parentheses

5y-3y+6

We add all the numbers together, and all the variables

2y+6

Back to the equation:

-(2y+6)



We add all the numbers together, and all the variables

7y-(2y+6)-12=0

We get rid of parentheses

7y-2y-6-12=0

We add all the numbers together, and all the variables

5y-18=0

We move all terms containing y to the left, all other terms to the right

5y=18

y=18/5

y=3+3/5

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