3y+4(y-6)=10y+3

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Solution for 3y+4(y-6)=10y+3 equation: 



3y+4(y-6)=10y+3

We move all terms to the left:

3y+4(y-6)-(10y+3)=0

We multiply parentheses

3y+4y-(10y+3)-24=0

We get rid of parentheses

3y+4y-10y-3-24=0

We add all the numbers together, and all the variables

-3y-27=0

We move all terms containing y to the left, all other terms to the right

-3y=27

y=27/-3

y=-9

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