3y+4-y+1=3-4y

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Solution for 3y+4-y+1=3-4y equation: 



3y+4-y+1=3-4y

We move all terms to the left:

3y+4-y+1-(3-4y)=0

We add all the numbers together, and all the variables

3y-y-(-4y+3)+4+1=0

We add all the numbers together, and all the variables

2y-(-4y+3)+5=0

We get rid of parentheses

2y+4y-3+5=0

We add all the numbers together, and all the variables

6y+2=0

We move all terms containing y to the left, all other terms to the right

6y=-2

y=-2/6

y=-1/3

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