3y+4-y=10+y+2

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Solution for 3y+4-y=10+y+2 equation: 



3y+4-y=10+y+2

We move all terms to the left:

3y+4-y-(10+y+2)=0

We add all the numbers together, and all the variables

3y-y-(y+12)+4=0

We add all the numbers together, and all the variables

2y-(y+12)+4=0

We get rid of parentheses

2y-y-12+4=0

We add all the numbers together, and all the variables

y-8=0

We move all terms containing y to the left, all other terms to the right

y=8

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