3y+40=-2(y+5)

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Solution for 3y+40=-2(y+5) equation: 



3y+40=-2(y+5)

We move all terms to the left:

3y+40-(-2(y+5))=0



We calculate terms in parentheses: -(-2(y+5)), so:

-2(y+5)

We multiply parentheses

-2y-10

Back to the equation:

-(-2y-10)



We get rid of parentheses

3y+2y+10+40=0

We add all the numbers together, and all the variables

5y+50=0

We move all terms containing y to the left, all other terms to the right

5y=-50

y=-50/5

y=-10

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