3y+40=300

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Solution for 3y+40=300 equation: 



3y+40=300

We move all terms to the left:

3y+40-(300)=0

We add all the numbers together, and all the variables

3y-260=0

We move all terms containing y to the left, all other terms to the right

3y=260

y=260/3

y=86+2/3

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