3y+40=68

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Solution for 3y+40=68 equation: 



3y+40=68

We move all terms to the left:

3y+40-(68)=0

We add all the numbers together, and all the variables

3y-28=0

We move all terms containing y to the left, all other terms to the right

3y=28

y=28/3

y=9+1/3

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