3y+43=7(y+1)

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Solution for 3y+43=7(y+1) equation:



3y+43=7(y+1)
We move all terms to the left:
3y+43-(7(y+1))=0
We calculate terms in parentheses: -(7(y+1)), so:
7(y+1)
We multiply parentheses
7y+7
Back to the equation:
-(7y+7)
We get rid of parentheses
3y-7y-7+43=0
We add all the numbers together, and all the variables
-4y+36=0
We move all terms containing y to the left, all other terms to the right
-4y=-36
y=-36/-4
y=+9

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