3y+4=1y+12

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Solution for 3y+4=1y+12 equation: 



3y+4=1y+12

We move all terms to the left:

3y+4-(1y+12)=0

We add all the numbers together, and all the variables

3y-(y+12)+4=0

We get rid of parentheses

3y-y-12+4=0

We add all the numbers together, and all the variables

2y-8=0

We move all terms containing y to the left, all other terms to the right

2y=8

y=8/2

y=4

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