3y+4=3(y+3)-5

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Solution for 3y+4=3(y+3)-5 equation: 


Simplifying
3y + 4 = 3(y + 3) + -5

Reorder the terms:
4 + 3y = 3(y + 3) + -5

Reorder the terms:
4 + 3y = 3(3 + y) + -5
4 + 3y = (3 * 3 + y * 3) + -5
4 + 3y = (9 + 3y) + -5

Reorder the terms:
4 + 3y = 9 + -5 + 3y

Combine like terms: 9 + -5 = 4
4 + 3y = 4 + 3y

Add '-4' to each side of the equation.
4 + -4 + 3y = 4 + -4 + 3y

Combine like terms: 4 + -4 = 0
0 + 3y = 4 + -4 + 3y
3y = 4 + -4 + 3y

Combine like terms: 4 + -4 = 0
3y = 0 + 3y
3y = 3y

Add '-3y' to each side of the equation.
3y + -3y = 3y + -3y

Combine like terms: 3y + -3y = 0
0 = 3y + -3y

Combine like terms: 3y + -3y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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