3y+4y+6(y-3)=47

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Solution for 3y+4y+6(y-3)=47 equation:



3y+4y+6(y-3)=47
We move all terms to the left:
3y+4y+6(y-3)-(47)=0
We add all the numbers together, and all the variables
7y+6(y-3)-47=0
We multiply parentheses
7y+6y-18-47=0
We add all the numbers together, and all the variables
13y-65=0
We move all terms containing y to the left, all other terms to the right
13y=65
y=65/13
y=5

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