3y+4z=16(y+z)

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Solution for 3y+4z=16(y+z) equation:


Simplifying
3y + 4z = 16(y + z)
3y + 4z = (y * 16 + z * 16)
3y + 4z = (16y + 16z)

Solving
3y + 4z = 16y + 16z

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-16y' to each side of the equation.
3y + -16y + 4z = 16y + -16y + 16z

Combine like terms: 3y + -16y = -13y
-13y + 4z = 16y + -16y + 16z

Combine like terms: 16y + -16y = 0
-13y + 4z = 0 + 16z
-13y + 4z = 16z

Add '-4z' to each side of the equation.
-13y + 4z + -4z = 16z + -4z

Combine like terms: 4z + -4z = 0
-13y + 0 = 16z + -4z
-13y = 16z + -4z

Combine like terms: 16z + -4z = 12z
-13y = 12z

Divide each side by '-13'.
y = -0.9230769231z

Simplifying
y = -0.9230769231z

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