3y+5(2-y)=2y-10

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Solution for 3y+5(2-y)=2y-10 equation: 



3y+5(2-y)=2y-10

We move all terms to the left:

3y+5(2-y)-(2y-10)=0

We add all the numbers together, and all the variables

3y+5(-1y+2)-(2y-10)=0

We multiply parentheses

3y-5y-(2y-10)+10=0

We get rid of parentheses

3y-5y-2y+10+10=0

We add all the numbers together, and all the variables

-4y+20=0

We move all terms containing y to the left, all other terms to the right

-4y=-20

y=-20/-4

y=+5

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