3y+5(3y-5)=11

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Solution for 3y+5(3y-5)=11 equation:



3y+5(3y-5)=11
We move all terms to the left:
3y+5(3y-5)-(11)=0
We multiply parentheses
3y+15y-25-11=0
We add all the numbers together, and all the variables
18y-36=0
We move all terms containing y to the left, all other terms to the right
18y=36
y=36/18
y=2

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