3y+50=7y-10

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Solution for 3y+50=7y-10 equation: 



3y+50=7y-10

We move all terms to the left:

3y+50-(7y-10)=0

We get rid of parentheses

3y-7y+10+50=0

We add all the numbers together, and all the variables

-4y+60=0

We move all terms containing y to the left, all other terms to the right

-4y=-60

y=-60/-4

y=+15

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