3y+5=2(y-1)

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Solution for 3y+5=2(y-1) equation: 



3y+5=2(y-1)

We move all terms to the left:

3y+5-(2(y-1))=0



We calculate terms in parentheses: -(2(y-1)), so:

2(y-1)

We multiply parentheses

2y-2

Back to the equation:

-(2y-2)



We get rid of parentheses

3y-2y+2+5=0

We add all the numbers together, and all the variables

y+7=0

We move all terms containing y to the left, all other terms to the right

y=-7

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