3y+5=2(y-3)+10

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Solution for 3y+5=2(y-3)+10 equation: 



3y+5=2(y-3)+10

We move all terms to the left:

3y+5-(2(y-3)+10)=0



We calculate terms in parentheses: -(2(y-3)+10), so:

2(y-3)+10

We multiply parentheses

2y-6+10

We add all the numbers together, and all the variables

2y+4

Back to the equation:

-(2y+4)



We get rid of parentheses

3y-2y-4+5=0

We add all the numbers together, and all the variables

y+1=0

We move all terms containing y to the left, all other terms to the right

y=-1

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