3y+6-y=8+y-4

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Solution for 3y+6-y=8+y-4 equation: 



3y+6-y=8+y-4

We move all terms to the left:

3y+6-y-(8+y-4)=0

We add all the numbers together, and all the variables

3y-y-(y+4)+6=0

We add all the numbers together, and all the variables

2y-(y+4)+6=0

We get rid of parentheses

2y-y-4+6=0

We add all the numbers together, and all the variables

y+2=0

We move all terms containing y to the left, all other terms to the right

y=-2

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