3y+7(y-3)=29

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Solution for 3y+7(y-3)=29 equation: 



3y+7(y-3)=29

We move all terms to the left:

3y+7(y-3)-(29)=0

We multiply parentheses

3y+7y-21-29=0

We add all the numbers together, and all the variables

10y-50=0

We move all terms containing y to the left, all other terms to the right

10y=50

y=50/10

y=5

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