3y+7-y=5+2(y+1)

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Solution for 3y+7-y=5+2(y+1) equation: 



3y+7-y=5+2(y+1)

We move all terms to the left:

3y+7-y-(5+2(y+1))=0

We add all the numbers together, and all the variables

2y-(5+2(y+1))+7=0



We calculate terms in parentheses: -(5+2(y+1)), so:

5+2(y+1)

determiningTheFunctionDomain
2(y+1)+5

We multiply parentheses

2y+2+5

We add all the numbers together, and all the variables

2y+7

Back to the equation:

-(2y+7)



We get rid of parentheses

2y-2y-7+7=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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