3y+7/4=27/4-y

Solution for 3y+7/4=27/4-y equation:

3y+7/4=27/4-y

We move all terms to the left:

3y+7/4-(27/4-y)=0


Domain of the equation: 4-y)!=0

We move all terms containing y to the left, all other terms to the right

-y)!=-4

y!=-4/1

y!=-4

y∈R


We add all the numbers together, and all the variables

3y-(-1y+27/4)+7/4=0

We get rid of parentheses

3y+1y-27/4+7/4=0

We multiply all the terms by the denominator


3y*4+1y*4-27+7=0

We add all the numbers together, and all the variables

3y*4+1y*4-20=0

Wy multiply elements

12y+4y-20=0

We add all the numbers together, and all the variables

16y-20=0

We move all terms containing y to the left, all other terms to the right

16y=20

y=20/16

y=1+1/4