3y+y+12=28

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Solution for 3y+y+12=28 equation: 



3y+y+12=28

We move all terms to the left:

3y+y+12-(28)=0

We add all the numbers together, and all the variables

4y-16=0

We move all terms containing y to the left, all other terms to the right

4y=16

y=16/4

y=4

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