3y-(5y+4)=12y-7(2y-1)

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Solution for 3y-(5y+4)=12y-7(2y-1) equation:


Simplifying
3y + -1(5y + 4) = 12y + -7(2y + -1)

Reorder the terms:
3y + -1(4 + 5y) = 12y + -7(2y + -1)
3y + (4 * -1 + 5y * -1) = 12y + -7(2y + -1)
3y + (-4 + -5y) = 12y + -7(2y + -1)

Reorder the terms:
-4 + 3y + -5y = 12y + -7(2y + -1)

Combine like terms: 3y + -5y = -2y
-4 + -2y = 12y + -7(2y + -1)

Reorder the terms:
-4 + -2y = 12y + -7(-1 + 2y)
-4 + -2y = 12y + (-1 * -7 + 2y * -7)
-4 + -2y = 12y + (7 + -14y)

Reorder the terms:
-4 + -2y = 7 + 12y + -14y

Combine like terms: 12y + -14y = -2y
-4 + -2y = 7 + -2y

Add '2y' to each side of the equation.
-4 + -2y + 2y = 7 + -2y + 2y

Combine like terms: -2y + 2y = 0
-4 + 0 = 7 + -2y + 2y
-4 = 7 + -2y + 2y

Combine like terms: -2y + 2y = 0
-4 = 7 + 0
-4 = 7

Solving
-4 = 7

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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