3y-(6y+5)-8=2(y+3)+5y-9

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Solution for 3y-(6y+5)-8=2(y+3)+5y-9 equation:



3y-(6y+5)-8=2(y+3)+5y-9
We move all terms to the left:
3y-(6y+5)-8-(2(y+3)+5y-9)=0
We get rid of parentheses
3y-6y-(2(y+3)+5y-9)-5-8=0
We calculate terms in parentheses: -(2(y+3)+5y-9), so:
2(y+3)+5y-9
We add all the numbers together, and all the variables
5y+2(y+3)-9
We multiply parentheses
5y+2y+6-9
We add all the numbers together, and all the variables
7y-3
Back to the equation:
-(7y-3)
We add all the numbers together, and all the variables
-3y-(7y-3)-13=0
We get rid of parentheses
-3y-7y+3-13=0
We add all the numbers together, and all the variables
-10y-10=0
We move all terms containing y to the left, all other terms to the right
-10y=10
y=10/-10
y=-1

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