3y-(y-4)=16

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Solution for 3y-(y-4)=16 equation: 



3y-(y-4)=16

We move all terms to the left:

3y-(y-4)-(16)=0

We get rid of parentheses

3y-y+4-16=0

We add all the numbers together, and all the variables

2y-12=0

We move all terms containing y to the left, all other terms to the right

2y=12

y=12/2

y=6

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