3y-(y-4)=4(2y-1)

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Solution for 3y-(y-4)=4(2y-1) equation: 



3y-(y-4)=4(2y-1)

We move all terms to the left:

3y-(y-4)-(4(2y-1))=0

We get rid of parentheses

3y-y-(4(2y-1))+4=0



We calculate terms in parentheses: -(4(2y-1)), so:

4(2y-1)

We multiply parentheses

8y-4

Back to the equation:

-(8y-4)



We add all the numbers together, and all the variables

2y-(8y-4)+4=0

We get rid of parentheses

2y-8y+4+4=0

We add all the numbers together, and all the variables

-6y+8=0

We move all terms containing y to the left, all other terms to the right

-6y=-8

y=-8/-6

y=1+1/3

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