3y-1+4/5+2y+4=5

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Solution for 3y-1+4/5+2y+4=5 equation: 



3y-1+4/5+2y+4=5

We move all terms to the left:

3y-1+4/5+2y+4-(5)=0

determiningTheFunctionDomain
3y+2y-1+4-5+4/5=0

We add all the numbers together, and all the variables

5y-2+4/5=0

We multiply all the terms by the denominator


5y*5+4-2*5=0

We add all the numbers together, and all the variables

5y*5-6=0

Wy multiply elements

25y-6=0

We move all terms containing y to the left, all other terms to the right

25y=6

y=6/25

y=6/25

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