3y-1+y+39=8y+40-6y

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Solution for 3y-1+y+39=8y+40-6y equation:



3y-1+y+39=8y+40-6y
We move all terms to the left:
3y-1+y+39-(8y+40-6y)=0
We add all the numbers together, and all the variables
3y+y-(2y+40)-1+39=0
We add all the numbers together, and all the variables
4y-(2y+40)+38=0
We get rid of parentheses
4y-2y-40+38=0
We add all the numbers together, and all the variables
2y-2=0
We move all terms containing y to the left, all other terms to the right
2y=2
y=2/2
y=1

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