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3y-10=3+2(-8y+3)
We move all terms to the left:
3y-10-(3+2(-8y+3))=0
We calculate terms in parentheses: -(3+2(-8y+3)), so:We get rid of parentheses
3+2(-8y+3)
determiningTheFunctionDomain 2(-8y+3)+3
We multiply parentheses
-16y+6+3
We add all the numbers together, and all the variables
-16y+9
Back to the equation:
-(-16y+9)
3y+16y-9-10=0
We add all the numbers together, and all the variables
19y-19=0
We move all terms containing y to the left, all other terms to the right
19y=19
y=19/19
y=1
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