3y-11=2(y-3)+6

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Solution for 3y-11=2(y-3)+6 equation: 



3y-11=2(y-3)+6

We move all terms to the left:

3y-11-(2(y-3)+6)=0



We calculate terms in parentheses: -(2(y-3)+6), so:

2(y-3)+6

We multiply parentheses

2y-6+6

We add all the numbers together, and all the variables

2y

Back to the equation:

-(2y)



We add all the numbers together, and all the variables

y-11=0

We move all terms containing y to the left, all other terms to the right

y=11

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