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3y-12=3(y+1)
We move all terms to the left:
3y-12-(3(y+1))=0
We calculate terms in parentheses: -(3(y+1)), so:We get rid of parentheses
3(y+1)
We multiply parentheses
3y+3
Back to the equation:
-(3y+3)
3y-3y-3-12=0
We add all the numbers together, and all the variables
-15!=0
There is no solution for this equation
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