3y-12=36-y+17

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Solution for 3y-12=36-y+17 equation: 



3y-12=36-y+17

We move all terms to the left:

3y-12-(36-y+17)=0

We add all the numbers together, and all the variables

3y-(-1y+53)-12=0

We get rid of parentheses

3y+1y-53-12=0

We add all the numbers together, and all the variables

4y-65=0

We move all terms containing y to the left, all other terms to the right

4y=65

y=65/4

y=16+1/4

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