3y-13(10)=23(y+40)

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Solution for 3y-13(10)=23(y+40) equation: 



3y-13(10)=23(y+40)

We move all terms to the left:

3y-13(10)-(23(y+40))=0



We calculate terms in parentheses: -(23(y+40)), so:

23(y+40)

We multiply parentheses

23y+920

Back to the equation:

-(23y+920)



We get rid of parentheses

3y-23y-920-1310=0

We add all the numbers together, and all the variables

-20y-2230=0

We move all terms containing y to the left, all other terms to the right

-20y=2230

y=2230/-20

y=-111+1/2

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