3y-18+4=7y+36

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Solution for 3y-18+4=7y+36 equation: 



3y-18+4=7y+36

We move all terms to the left:

3y-18+4-(7y+36)=0

We add all the numbers together, and all the variables

3y-(7y+36)-14=0

We get rid of parentheses

3y-7y-36-14=0

We add all the numbers together, and all the variables

-4y-50=0

We move all terms containing y to the left, all other terms to the right

-4y=50

y=50/-4

y=-12+1/2

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